-x^2+2x-4x=8

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Solution for -x^2+2x-4x=8 equation: 



-x^2+2x-4x=8

We move all terms to the left:

-x^2+2x-4x-(8)=0

We add all the numbers together, and all the variables

-1x^2-2x-8=0

a = -1; b = -2; c = -8;
Δ = b2-4ac
Δ = -22-4·(-1)·(-8)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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